tag:blogger.com,1999:blog-8850795848027608997.post3809924322899294655..comments2021-06-11T23:26:30.830-07:00Comments on Majia's Blog: FUKUSHIMA EMISSIONS FAR GREATER THAN REPORTEDMajia's Bloghttp://www.blogger.com/profile/04941091700194936591noreply@blogger.comBlogger10125tag:blogger.com,1999:blog-8850795848027608997.post-30012890074906944812012-11-26T00:02:40.503-08:002012-11-26T00:02:40.503-08:00http://neucleardisaster.blogspot.com/http://neucleardisaster.blogspot.com/Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-8850795848027608997.post-84920170142635942972012-10-06T09:30:24.705-07:002012-10-06T09:30:24.705-07:00Thank you very much for explaining Werner.
The th...Thank you very much for explaining Werner.<br /><br />The theorists' abstract numerical representations of death-causing elements rationalize nuclear and allow the psychological detachment necessary for the perpetuation of this insanity.<br /><br />Thank you for unpacking the fundamental uncertainty at the heart of these detached mathematical formulations.<br /><br />Max Weber was correct about the potential for evil in bureaucratic rationalization.Majia's Bloghttps://www.blogger.com/profile/04941091700194936591noreply@blogger.comtag:blogger.com,1999:blog-8850795848027608997.post-77667219865204201132012-10-05T13:15:39.535-07:002012-10-05T13:15:39.535-07:00Majia, Mr Arnie Gunderson were referring to temper...Majia, Mr Arnie Gunderson were referring to temperatures above boiling points.<br />The characteristic of the graphs changes several times during the meltdown process<br />and many constants have been derived for low temperatures which don’t apply for high temperatures. It not rare to see speculations being underestimated in all calculations from cancer fatalities to Bq to Sv. Although uneducated myself and<br />not by authority to criticize the work of others, much more energy could have been released than what calculations can provide. Some calculations have possibly given <br />a ‘divide by zero’ error in the past, causing them to devise a workaround instead of believing it is impossible according to the formula. The methods described are not transportable anywhere else, but are easy and applicable to show a continuation of a pattern up to the melting point. Constants are intertwined in an endless bucket of formulas. Change one constant and you have to change them all. One small estimation error per atom can result in millions dying.<br />Werner Potgieterhttps://www.blogger.com/profile/00848408111342348135noreply@blogger.comtag:blogger.com,1999:blog-8850795848027608997.post-25868811196471040712012-10-05T12:21:40.527-07:002012-10-05T12:21:40.527-07:00For Plutonium with a melting point of 912.5 K, and...For Plutonium with a melting point of 912.5 K, and a constant volume molar heat capacity of 35.5 J/(mol·K) at 298 K , we will be out of range for Figure 6 as early as 289 K, with significant volume changes between 300 K and 1000 K also drastically changing approximations.Werner Potgieterhttps://www.blogger.com/profile/00848408111342348135noreply@blogger.comtag:blogger.com,1999:blog-8850795848027608997.post-28592356593725176042012-10-04T08:42:10.355-07:002012-10-04T08:42:10.355-07:00Werner can you translate your analysis for readers...Werner can you translate your analysis for readers.<br /><br />What are the implications of your calculations?<br /><br />What do they tell us about Fukushima?<br /><br />Thank youMajia's Bloghttps://www.blogger.com/profile/04941091700194936591noreply@blogger.comtag:blogger.com,1999:blog-8850795848027608997.post-37582403412745759982012-10-03T16:24:03.763-07:002012-10-03T16:24:03.763-07:00http://arxiv.org/pdf/1209.0648.pdf
The power func...http://arxiv.org/pdf/1209.0648.pdf<br /><br />The power function model applied to figure 6 yields a different outcome:<br /> heat capacity cp = 35 J/(mol • K)<br /> thermal conductivity = 46 W/(m • K)<br /> temperature = 1526 K<br />where graphs collide. Figure 5 and 6 are both out of range for those values.<br />Playing with models is certainly not a good thing when it comes to accuracy, but compare this to the green graph of figure 2.<br />Werner Potgieterhttps://www.blogger.com/profile/00848408111342348135noreply@blogger.comtag:blogger.com,1999:blog-8850795848027608997.post-89124689269857209842012-10-01T19:28:24.824-07:002012-10-01T19:28:24.824-07:00Example of calibration and turning of axis for Fig...Example of calibration and turning of axis for Figure 6:<br />Turn the graph 90deg anti-clock wise. Calibrate the x-axis from 0 to 52.5 where the <br />graph will become out of range after 28. Start with zero left and 52.5 at the right end.<br />Keep the same graphical lay-out as these will be converted later. <br />Complete a mirror image of the right part of the graph at the following point:<br />T at 121.692 K and heat capacity cp = J/(mol • K) at 23.437 by re-scaling both axis to a maximum of 15. In this new range you have kept the graphs in position and they are as follows:<br />Line y = mx + c where m = -1.7 and c = 13.28<br />Hyperbola xy = 1.7 <br />These intercept at the following point:<br />x2 -7.8x + 1 = 0<br />Re-scaling the root 13.08 to the initial scale is (13.08/15) x 1400 = 1220.8 K<br />where red and blue collide. This method is very useful if you don’t have Mathematica 5.2-6.0, Maple 10, or Matlab 7.0 at home utilizing multiprocessor calculations or aren’t able to use a Runge-Kutta method of 8-9th order and the numerical methods of lines or are not a graduate. The numerical error estimate didn't exceed 0.015% in addition to the existing 0.01% at the high point of interception.<br />We now have confirmation of figure 6 and it doesn’t help us at all.<br />Werner Potgieterhttps://www.blogger.com/profile/00848408111342348135noreply@blogger.comtag:blogger.com,1999:blog-8850795848027608997.post-39139972515874824592012-09-30T05:28:13.987-07:002012-09-30T05:28:13.987-07:00Changing the gradient of a straight line while plo...Changing the gradient of a straight line while plotting it results in a hyperbola, when the product of your values is a constant. In addition to this: the perfect mathematical model always assumes infinity, therefor truncating the graph at a low value immediately changes your value to a 1/infinity value. You might find yourself swopping the x or y value with a constant while using the constant for the x or y value<br />as it changes out of range. In essence a hyperbola insists that a high value of x is a low value for y and vice versa except in the low values for both. Rotating the axis might give you that effect, provided that you rotate it at the correct place and calibrate the current highest and lowest value. When both values increase simultaneously the hyperbola theory crashes as much as the line theory crashes when the gradient changes and there is the logarithmic theory etc. The problem is scale, and nuclear disaster is scalar problem to take note of. Now try |ABSOLUTE CONSTANT| = XY.<br />Thank you.<br />Werner Potgieterhttps://www.blogger.com/profile/00848408111342348135noreply@blogger.comtag:blogger.com,1999:blog-8850795848027608997.post-68445569394357020132012-09-29T07:00:25.978-07:002012-09-29T07:00:25.978-07:00http://arxiv.org/pdf/1209.0648.pdf
Since proportio...http://arxiv.org/pdf/1209.0648.pdf<br />Since proportionality is obtained by emulating experiments of limited temperature ranges and modelling them according to known values, let us try the following model: rotate the y-axis by 180 degrees to have zero on top and 27 at the bottom. A hyperbola y = contant / x is what you will see from modelled figure 6. There are many constants found in models: (also try y = x / constant) 2nd order temperature dependency, const = 4.19 J / (cm x cm x cm x s x K x K), specific heat capacity at constant pressure determined by value cp = 6 cal/(mol x deg), heat capacity = 11.5 J/(K x mol)… which takes us to another simple hyperbola z = En / kT. Co-joining the exact determined modelled value to respective x and y axis at the part closest thereby where the ranges are terminated, leaves us with the following assumption: there is infinity above the graph and (1 / infinity) below the graph. With respect to each other: infinity minus (1 / infinity) = infinity. Values above the arranged collection of points are not affected below them, since they are not connected in any manner and cannot be connected, is what the assumption imply. Very few accurate experiments were able to be performed to determine constants of high temperature due to limitations.<br />The scattering of the i th fissile nuclide is i th catastrophic.<br />Werner Potgieterhttps://www.blogger.com/profile/00848408111342348135noreply@blogger.comtag:blogger.com,1999:blog-8850795848027608997.post-67395822669440079892012-09-24T12:08:25.290-07:002012-09-24T12:08:25.290-07:00The SPEEDI data is only as good as the source term...The SPEEDI data is only as good as the source term of the radiation that is plugged into it.<br /><br />I have seen a picture of steam & smoke coming out of stack #1 from the time in between the earthquake hit and the tsunami. It was probably spitting out radiation before the earth stopped trembling.Bobby1http://optimalprediction.com/wp/noreply@blogger.com